Help with molar concentration problems
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Prepare 0.06 mol of α-bromophenylpropanone along with 12.6 grams of benzene. How much benzene do you need?
This post was last edited by qugd on 2020-6-18 09:54. Can’t you do the calculations yourself? You need to clarify whether benzene is used as a solvent If benzene is the solvent, then everything other than the solute is benzene; it doesn’t matter how much there is. Use a volumetric flask to determine the volume, and add solute until the mark is reached. The amount of benzene is related to the total volume of the solution you prepare. It seems like you haven’t studied high school chemistry.
α-bromophenylpropanoic acid with a molecular weight of 213.07； 12.6 grams is exactly 0.06 moles; if what you’re referring to is 0.06 moles per liter, then you can use a 1L volumetric flask and fill it to the mark.