The manufacturer specifies that the pump’s head is 10m; so how far can it transport water horizontally?
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This post was last edited by HaiChuanXiaoDangJia on 2019-2-22 at 11:58. I searched for other posts on this forum; they’re too professional and I can’t understand them. Some say that 10 meters of head converts to a horizontal conveying distance of 100 meters. I understand this statement... For example, the manufacturer provides parameters such as the inlet and outlet diameters as well as the specified head. Assuming that a pipe of infinite length is connected to the pump’s outlet (with a diameter chosen according to the manufacturer’s specifications), and ignoring factors like energy loss, then the water will stop flowing after 100 meters. 【I. Is this statement correct?】 For a fire pump with a head of 10 meters, assuming that a hose of length x meters is connected to the pump’s outlet, and that the energy loss in that hose is a meters, then for horizontal flow, the maximum spraying distance will be 100 meters minus a meters. 【II. Is this sentence correct?】 【III. For head, is there a conversion formula to convert it into horizontal transport distance?】 Or based on practical experience, I think in reality it’s necessary to account for some losses and consider certain parameters. 】 Please, experts, explain this in simple terms; you can give examples so that we can get a general idea. In practice, we will use it, and it’s sufficient to understand the basic principles. Thank you, experts!
The range indicated on the nameplate of a water pump generally refers to the distance in the horizontal direction; 10 meters for horizontal movement, and less than 5 meters for vertical movement
This post was last edited by li*nji on 2019-2-22 at 16:13. The head of a pump refers to the height to which the pump can lift water; the horizontal distance over which water can be transported is determined mainly by the resistance to flow within the pipes, and it is related to the diameter of those pipes. Generally, for a pipe with a diameter of 350 mm, the head loss over a transmission distance of 300 meters is equivalent to that of a lift of 10 meters. In other words, a pump with a lift of 10 meters can deliver water steadily over a distance of 300 meters in a 350-mm-diameter pipe; beyond 300 meters, the pumping resistance increases. The pipe is narrow, resulting in a significant increase in resistance. It is recommended to refer to the \"Code for Design of Building Water Supply and Drainage\" GB50015-2010
If energy loss is ignored, the urine you produce in the morning could be shot into outer space.
Thanks, friend. I’m somewhat familiar with it; I’ll look into this standard later
Then fly across a few light-years to strike at the aliens’ lair, right! :Lol, say something useful – I really don’t understand, my lifetime member friend
This post was last edited by 3983596_FPPZ on 2019-2-23 08:47. Some say that 10 meters of head corresponds to a horizontal conveying distance of 100 meters. I understand this statement... For example, the manufacturer provides parameters such as the inlet and outlet diameters as well as the specified head. Assuming that a pipe of infinite length is connected to the pump’s outlet (with a diameter chosen according to the manufacturer’s specifications), and ignoring factors like energy loss, then the water will stop flowing after 100 meters. 【This statement is incorrect; if there were no energy losses, a slight lift would allow the water to be transported over an infinite distance. Just as a liquid starts moving when subjected to a force, it can maintain uniform linear motion in the absence of resistance losses. Therefore, the distance of several light-years mentioned by the previous user is theoretically reasonable.】 In the case of a fire pump with a lift of 10 meters, assuming that a hose of length x meters is connected to the pump’s outlet, and if the energy loss in that hose is a certain amount, then the maximum distance over which water can be sprayed horizontally is 100 meters minus a. The head of a pump can be understood as the height to which water can be lifted vertically; the energy required for this elevation (potential energy) is what constitutes the head, not the horizontal distance. It’s not accurate to assume that a head of 10 meters means the water can be transported over a distance of 100 meters – this depends on factors such as flow rate, viscosity, pipe diameter, and pipe wall roughness (which causes losses). Long-distance transportation is primarily affected by frictional losses; it depends on how much of the energy provided by a 10-meter head can compensate for those frictional losses over a certain distance, which in turn determines how far material can be transported. » » III. Regarding head: is there a formula to convert it into a horizontal transportation distance? Or based on practical experience, I think in reality it’s necessary to account for some losses and consider certain parameters. 】Calculation method for frictional losses: https://bbs.hcbbs.com/thread-2140100-1-1.html. Head is essentially an energy value of mgH; since it needs to be expressed per unit weight of liquid, the energy is divided by the unit weight/mg, resulting in a height unit of meters. How this energy is utilized depends on the purpose: whether it is used to raise the liquid to a certain height (in which case the increase in potential energy must be taken into account), or for transporting the liquid over a horizontal distance (with the energy being spent on frictional and local losses), or for both purposes.
It’s easy to understand; thanks for taking the time to reply!
The first sentence is incorrect, the second sentence is also incorrect; the third sentence simply converts the head into a pipe friction loss. Using software will be much faster.