For a gas boiler, how much air is required to burn 10,500 NM3/h of natural gas?
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For a gas boiler, how much air is required to burn 10,500 NM3/h of natural gas? If anyone who knows how to do this can help calculate it, I’m waiting online. . . . . . . . . . . . . . .
If it is methane, the air volume is 10 times the fuel volume
The main component of natural gas is methane; based on the combustion equation for methane, the theoretical air volume is 100,000 Nm3/h, with an excess air coefficient of around 1.1. If the specific composition of the natural gas is known, more accurate values can be calculated. . .
Is there a formula? How was it calculated? Please give an answer!
Gas composition: Volume percentage H2 C1 C2 C3 C4-neg N2 0 0.96226 0.0177 0.00437 0.00125 0.01442 Could you explain the calculation process in detail?
Based on the combustion reaction equations: CH4 + 2O2 = CO2 + 2H2O, 2C2H6 + 7O2 = 4CO2 + 6H2O…… the amount of O2 is calculated, and then the amount of air is determined by using the fact that O2 makes up 21% of air. . . .
A simple empirical formula: lol
Theoretically, it is 1:10; considering a surplus factor of 1.1, the actual efficiency will not be that high – the surplus factor should be considered at least as 1.2.
What are the high calorific value and low calorific value?