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This post was last edited by 000245 on 2018-12-29 14:37. When I recently calculated the weight of a conical head, I found that the result calculated by the formula in GB/T25198-2010 was very different from the actual weight. The parameters of the conical head are: The big end is DI 2425, the small end is DI 1182, and the wall thickness is 8mm. The angle is 58°, the half angle is 29°, and the big end is hemmed R150. Calculated using CHA (30/45) on page P19 of the standard, it is about 2000KG. The 3D drawing using SOLIDWORKS is 500KG. Because the size of the blanking steel plate is known, the quality attributes on the SW should be accurate. So is the formula in the standard only suitable for tapered heads with a half-angle of 30 or 45 degrees? Looking at the calculation process, the angle is also substituted. Why?
Is this tapered head used in normal pressure vessels? The big end folding radius does not comply with GB150 regulations.
Specifically, you can use 3D software to model the quality, center of gravity and other basic physical parameters like the original poster, and the results can be automatically generated to be more accurate.
This post was last edited by zjq1962 on 2018-12-29 16:33. If it is designed according to GB/T150, the folding radius of the big end of the cone head shall not be less than 10% of the inner diameter of the big end. From your diagram and calculation book, there is no problem. Your initial text description is R150
Maybe the EXCEL formula was compiled incorrectly! Check it carefully again.
I should have calculated it according to the standard formula, 495.6kg.
May I ask where you can find the parameter formulas for C1, C2 and C3?
When using EXCEL to calculate angles, pay attention to the conversion between radians and angles, and also pay attention to the units used.
I use this method: Draw the figure proportionally in the drawing software, and measure the unilateral cross-sectional area and the distance from the cross-section center to the center line as the radius of gyration. Calculate the volume of the rotary body and the weight will be found.