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Calculation method for the volume of the insulation layer on the reactor head

2017-05-19View Original

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For the DN1900 head, with a thermal insulation layer of 100, how should the thickness of this insulation layer be calculated? I read online that it’s sufficient to use the area of a circular shape with a diameter of DN1900, multiplied by 1.66 and then by 0.1. I’m not sure if this method works; how should the calculation be done accurately?

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