One Question per Day in Applied Chemistry 8-8~8-9
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This post was last edited by coolmaokai on 2017-8-8 09:12. Utilizing knowledge related to applied chemistry, including (analytical chemistry, physical chemistry, and principles of chemical engineering), we are launching the \"One Question per Day\" activity; replies will reveal the questions. To encourage continued participation from everyone! You get 3 wealth rewards just for participating! Correct answers earn an additional 5 wealth rewards. I hope everyone will participate actively, learn together, and make progress together! ! ! Try to come up with some questions that people can’t find easily; please use your mouse or pen to do the calculations carefully~ Thank you. In an open-air factory building, a pipe has a horizontal length of 5 meters and a vertical length of 20 meters, with the inner wall temperature of the pipe at 525 degrees Celsius. What are the horizontal and vertical expansion amounts? (5 points worth of rewards; please provide the calculation process.) If the fluid inside the pipe is heavy, is there a more reliable way to install the expansion joint? (Bonus questions: 1–50 points; no limit on rewards.) Take a = 0.0133 mm/m; the horizontal dimension is 32.5 mm, and the vertical dimension is 130 mm
32.5 mm in width and 130 mm in length
32.5 mm in width and 130 mm in length
32.5 mm in width and 130 mm in length
32.5 mm in width and 130 mm in length
Assuming an installation environment temperature of 25°C: horizontal expansion: 5*0.0133*（525-25）=33.25mm, vertical expansion: 20*0.0133*（525-25）=133mm
The unit for leakage is probably per °C. Horizontal expansion = 5*0.0133*（525-Tam）≈33.58; vertical expansion = 20*0.0133*（525-Tambinet）≈134.33. The expansion joint is installed at the corner above the elbow, and its purpose is mainly to compensate for vertical expansion, with the horizontal expansion of the pipe being converted into horizontal displacement.
Elbows are used at the connection points, and supports and hangers are installed to ensure safety during maintenance
The expansion amount △L = 5×(525–20)×0.0133 = 33.58 mm. The expansion amount △L = 20×(525–20)×0.0133 = 134.33 mm.