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Please help me calculate the resistance and height based on the simple diagram.

2019-07-12View Original

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The concentration of the material is 90%. Please help me calculate the height based on the diagram, or give me a formula or an idea. Thank you gods
Reply #22019-07-12
The viscosity of the material, the diameter of the pipe, and the volume of the tank are all parameters that cannot be calculated.
Reply #32019-07-12
Can it be calculated if these parameters are provided?
Reply #42019-07-13
Separator liquid density (ρ points), absorbent density in the absorption tower (ρ suction), absorbent liquid level height (h suction). Flows through the absorption tower by its own weight. When passing through an absorption tower, the height that the liquid level in the separator needs to increase compared to the liquid level in the absorption tower is: (ρ suction-ρ points)/ρ points * h suck. Through four absorption towers, multiply by 4. Is it okay to think about it this way?
Reply #52019-07-18
You'd better add a pump in the middle instead of saving money. The water column is only 0.1Mpa at 10 meters, and the jar must be placed at a height of 10 meters. There are also 4 absorption tanks. There is a problem with this idea. Of course, in theory, if the tank is slightly higher, it will flow through, but what about your flow rate? Not realistic.
Reply #62019-07-19
An extremely complex issue, but you made it very simple.
Reply #72019-07-29
This post was last edited by Look Up Air on 2019-7-29 10:15 to compare the density difference between the adsorbent and the condensate. Make the Rough of the condensate greater than that of all adsorbents. The influence of pipeline resistance drop is not considered here.
Reply #82019-07-29
;P It would be much better if you change the vertical type to a horizontal type.

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