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Given that the temperature of the water is 90 degrees Celsius, the pressure is at atmospheric level, and the diameter of the open tank is 1.8 meters, what is the evaporation rate per hour? Or how much water needs to be added per hour to maintain the liquid level? Please help me solve this! Waiting online, it’s quite urgent
Evaporation is related to air humidity and wind speed; 90°C, E=701.17 hPa. e150 refers to the saturated vapor pressure at a height of 150 cm above the water surface multiplied by the relative humidity; it can be determined using tables or measurements, and its unit is hPa ; u150 refers to the wind speed at 150 cm above the water surface, in m/s ; The unit for W is mm/d
If the room temperature is 20 degrees Celsius indoors, how many parameters can be determined with accuracy? Where can I look up the table?
The saturated vapor pressure at a room temperature of 20°C is 23.38 hPa, and relative humidity can be measured using a hygrometer; In indoor areas, if forced ventilation is not available, a rough estimate of 0.1~0.2 m/s can be used ; It’s best to measure it with an anemometer, or an estimation will also work.
Using this formula, the evaporation rate for a tank with a diameter of 1.8 meters is a little over 16 kilograms per hour; it seems a bit off. Could the units be incorrect?
Also, is the temperature of your water kept at 90°C? If the initial temperature is 90°C, it will gradually decrease as evaporation occurs.
The water maintains a constant temperature, with a heat source providing additional heat
It’s pretty accurate. You can imagine that when water is boiled in a pot, it will dry up after a while; moreover, the diameter of the pot isn’t even 1.8 meters, so the temperature difference of eight or nine degrees isn’t significant.
It’s a pretty big difference, right? You can imagine it: water in a bowl during the summer doesn’t have such a high temperature. Assuming 18 kilograms of water, at 90°, 2 millimeters evaporate per hour – which is a bit little