Issues regarding the calculation of accuracy for pressure and differential pressure transmitters
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As shown in the figure: it is stated that when choosing a transducer with a range ratio of less than 10:1, the accuracy should be calculated using this formula. For example, if the upper limit of the range is 13789.51 kPa and the range extends from –13789.51 kPa to 13789.51 kPa, what would be the accuracy if the range is set to –500 to +500? What is the range ratio? My understanding is as follows: the range is from –13789.51 kPa to 13789.51 kPa. Therefore, 13789.51 * 2 = 27579.02, and 500 * 2 = 1000; thus, the range ratio is 27579.02:1000, which is approximately 28:1. Using the formula, the accuracy is equal to ±(0.015 + 0.005 * (13789.51/1000)), which equals ±0.08394755%. Hence, the accuracy of the transmitter within this range is approximately ±0.084%. This is my personal opinion; I would appreciate it if those with more experience could check whether my understanding is correct Thank you.
Fails to adapt to Western styles, uses inappropriate wording; the translation is terrible – as bad as foreign trash...... Inspection complete.
Your calculation is also wrong. “\"Upper range limit\" should have been translated as \"full scale\"; \"full span\" is a more appropriate translation. The person who wrote this translation is a complete idiot.
The terms \"upper range limit\" and \"range\" in Chinese are indeed not easy to understand; it becomes clearer when referring to the English manual
I checked; the upper limit of the range is URL, and the range itself is Span
:Lol 1. You’re basically asking what it means to translate a URL into Chinese, right? . . I’ve always hated those spooky-looking foreign letters used for swords. 2. If the standard measurement ranges of the instrument are -100~0 kPa for one and 0~-100 kPa for the other, what do you consider to be the upper limit of the range in each case? 3. Substitute the value you consider to be the \"upper range limit\" into the precision calculation formula you are using, and check whether the resulting value is reasonable......... :lol