Hydrogen flow rate and volume in methanol-to-hydrogen process
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For hydrogen production from methanol, with an output of 1400 NM3 standard cubic meters per hour (at a rated methanol feed rate of 900 KG/H), is the volume measured in cubic meters when it passes through the gas holder (1000 cubic meters) and reaches the inlet of the hydrogen compressor? The hydrogen compressor has a gas delivery rate of 36 m3/min; the inlet pressure is 480 mm of water column, while the outlet pressure is 26.5 MPA. It features six stages of compression. How does one calculate the conversion between standard cubic meters and m3? I’ll provide any additional relevant information if needed. Is there anyone who can help answer this? Thank you very much.
The hydrogen production rate from methanol is 1400 Nm3 per hour (on a standard volume basis), while the gas flow rate at the inlet of the hydrogen compressor is 36 m3/min. To convert between these two units, it is first necessary to define them: 1. Standard cubic meter (Nm3): It refers to the volume of a gas at standard atmospheric pressure (101.325 kPa) and standard temperature (273.15 K). 2. Cubic meter (m3): It is a basic unit that represents volume in three-dimensional space. Since the standard volume is the gas volume under standard conditions, and the gas entering the hydrogen compressor inlet does not necessarily meet these standard conditions, it needs to be converted into cubic meters. The conversion formula is: 1 Nm3 = 1.01325 m3 (at standard atmospheric pressure). Using the provided information, it can be calculated that 1400 Nm3 per hour equals 1400 * 1.01325 = 1418.55 m3/h. Therefore, the hydrogen production rate from methanol, based on 1400 Nm3 per hour, is approximately 1418.55 m3/h. The air delivery volume of the hydrogen compressor is 36 m3/min, which is 2160 m3/h. I hope the above information will be helpful to you! .
Thank you so much for answering my questions!
Based on the law of conservation of mass, it can be calculated using the ideal gas law.