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English Translations » 汽提再生硫磺回收 » Sulfur Recovery Daily Question 2018.9.2

Sulfur Recovery Daily Question 2018.9.2

2018-09-02View Original

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Question: Explain the dual nature of oxidation and reduction of sulfur dioxide using chemical reaction equations. Answer: SO2 is both oxidizing and reducing. For example: 2H2S+SO2===2 H2O+3/xSx (note: X is 2, 6, 8). 2SO2+O2 === 2SO3; therefore, sulfur dioxide can be used as a bleaching agent to fade many colored substances.
Reply #22018-09-02
SO2 is both oxidizing and reducing. For example: 2H2S+SO2=2 H2O+3/xSx (Note: X is 2, 6, 8)
Reply #32018-09-02
2H2S+SO2===2H2O+3/xSx (Note: X is 2, 6, 8) 2SO2+O2===2SO3
Reply #42018-09-02
Answer: SO2 is both oxidizing and reducing. For example: 2H2S+SO2=2 H2O+3/xSx (Note: X is 2, 6, 8)
Reply #52018-09-02
Reductive: SO2 + 2H2S = 2H2O + 3/XSX; Oxidizing: 2SO2 + O2 = 2SO3
Reply #62018-09-02
This post was last edited by Hurried Passerby on 2018-9-2 at 11:34. 2H2S + SO2 = 2H2O + 3/xSx (Note: X can be 2, 6, or 8)； 2SO2+O2=2SO3
Reply #72018-09-02
SO2 is both oxidizing and reducing. For example: 2H2S+SO2===2 H2O+3/xSx (Note: X is 2, 6, 8)
Reply #82018-09-02
SO2 is both oxidizing and reducing. For example: 2H2S+SO2===2 H2O+3/xSx (note: X is 2, 6, 8). 2SO2+O2 === 2SO3; therefore, sulfur dioxide can be used as a bleaching agent to fade many colored substances.
Reply #92018-09-02
SO2 is both oxidizing and reducing. For example: 2H2S+SO2===2 H2O+3/xSx (note: X is 2, 6, 8). 2SO2+O2 === 2SO3; therefore, sulfur dioxide can be used as a bleaching agent to fade many colored substances.
Reply #102018-09-02
SO2 is both oxidizing and reducing. For example: 2H2S + SO2 === 2H2O + 3/2S; 2SO2 + O2 === 2SO3. Therefore, sulfur dioxide can be used as a bleaching agent to fade many colored substances.
Reply #112018-09-02
SO2 is both oxidizing and reducing. For example: 2H2S+SO2=2 H2O+3/xSx (Note: X is 2, 6, 8)

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Translated at 2026-07-23 11:37:28

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