How is the linear speed of a mechanical seal calculated?
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This post was last edited by 156026692 on 2019-5-19 at 13:34. I’m asking how to calculate it – how to determine the linear velocity of a mechanical seal? Why is the linear velocity 13.0 when the rotation speed is 2950 rpm, the shaft diameter is 55 mm, and the average diameter of the sealing surface is 60.5 mm?
The unit of linear velocity is m/s. One full rotation covers a distance equal to πD, which is 3.14159*60.5/1000 = 0.19 meters. With a rotational speed of 2950 r/min, that means 2950 rotations per minute; therefore, the number of rotations per second is 2950/60 = 49.1667 rotations per second. Hence, the linear velocity is 0.19*49.1667 = 9.345 m/s. Average diameter (mid-diameter) = (inner diameter + outer diameter)/2. The linear velocity of 13.09 m/s you have might have been calculated based on the outer diameter; please verify this, as the linear velocity is independent of the shaft diameter.
13.09 I don’t know how it was calculated
Do I need software for calculating linear velocity?