What is the impact of pressure on a weighing instrument?
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What is the impact of pressure on a weighing instrument? For example: at a pressure of 2 kilograms, the scale reads 100 kg. Under unchanged conditions, what will be the scale’s reading at a pressure of 1 kilogram? (I hope everyone can provide the specific calculation process or empirical values; thank you!) ) 90
This is simple physics knowledge: pressure should refer to stress, and the force exerted by atmospheric pressure on an object equals stress multiplied by area
The environment surrounding the weighing instrument – that is, the pressure in that area – has little impact, as you said; however, a pressure difference might have an effect.
If a force of 2 kg is applied to the scale and it reads 100 kg, then applying a force of 1 kg should result in a reading of 50 kg, which is exactly half； The formula is 2:100=1:X; X=100*1/2=50 kg. This is my personal understanding for discussion purposes
How can one draw conclusions from just one set of data?
If the object being weighed is a pressure vessel with only internal pressure changes, this has little impact on the weighing result; the reading will decrease slightly. If the force is applied directly to the object, then it’s simple: multiply the pressure by the area over which it acts on the scale, convert that value to weight, and add it to the original reading – that should give the correct reading. Personal opinion
This is probably a calculation problem. The pressure in physics is referred to as stress, denoted as P = F/S. Here, F represents the gravitational force generated by the weight of the object, which is given by F = Mg, where M = 100 kg. We can set up the equations as follows: P1 = 100*g/s, P2 = M2*g/s. Therefore, P1/P2 = 100/M2. Substituting the values, we get 2/1 = 100/M2, from which it follows that M2 = 50 kg
This is probably a calculation problem. The pressure in physics is referred to as stress, denoted as P = F/S. Here, F represents the gravitational force generated by the weight of the object, which is given by F = Mg, where M = 100 kg. We can set up the equations as follows: P1 = 100*g/s, P2 = M2*g/s. Therefore, P1/P2 = 100/M2. Substituting the values, we get 2/1 = 100/M2, from which it follows that M2 = 50 kg
Let’s not discuss this post anymore; the original poster didn’t explain things clearly. What should be done if a steel cylinder with a pressure of 2 kilograms is placed on a scale and the pressure is adjusted to 2 kilograms? Or what should be done if a pneumatic piston exerts pressure on the scale, causing the pressure to change?
Could you explain in more detail how increased internal pressure leads to a decline in the quality of reading clubs? Because we are currently facing such a problem: with a tank weight of 30 tons, after pressurizing it with nitrogen to 0.6 MPa, the tank weight drops to 23 tons. It’s baffling; I’m very frustrated.