Regarding PI regulation
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In single-loop automatic control, regarding the opening degree of the PI control valve, the higher the frequency P, the greater the effect on the valve; similarly, the higher the value of I, the greater the impact on the valve.
The larger P is, the stronger the proportional action, the greater the output, and the greater the valve’s movement amplitude. The larger I is, the stronger the integral effect, the greater the output, and the greater the valve’s movement amplitude.
P’s statement is correct, but I’s statement is wrong; the larger I is, the weaker it becomes. :D
I is for controlling the deviation, right? P is correct
P’s statement is correct; it refers to the magnification factor. I represents the integration time – the smaller I is, the shorter the integration time and the stronger the effect.
This question is not rigorous. P refers to the proportional control law; there are two parameters that describe the strength of proportionality: one is the proportional gain Kp, and the other is the proportional degree δ ； I refers to the integral control law; the strength of integration is usually described by the integration time Ti, and another parameter is the integration rate Ki. For example, the larger the amplification factor Kp, the smaller the proportionality constant δ; a stronger proportional action results in a reduced residual error in the control system, while at the same time the system tends to oscillate ； The smaller the integration time Ti, the larger the integration rate Ki and the stronger the integrating effect; as a result, the residual error is eliminated more quickly, while the system tends to oscillate.