Thin-walled sleeve with end sealing. Small holes with a diameter of less than 4 mm are made in the sleeve; natural gas passes through these holes. How is resistance calculated?
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1) The diameter of the sleeve is 38*3, with material Q235. 2) The medium inside the sleeve is natural gas. 3) The pressure inside the sleeve is 1.5 bar (g). 4) The flow velocity inside the sleeve is 80 m/s at a pressure of 1.5 bar. 5) The ends of the sleeve are sealed. 6) There are 6 small holes evenly distributed around the sleeve, with a diameter of 4 mm; the outside of these holes is in contact with the atmospheric environment. Question: How can the flow velocity of the air passing through these holes be calculated? The resistance through the small hole?
The outer layer is the atmospheric environment – is it still necessary to calculate this flow rate? Is the thing you made the eternal flame on a torch?
It’s not a perpetual light; it requires a very high combustion efficiency. It is a combustion device in the chemical processing system.