Regarding the issue of choosing polar or non-polar for Aspen property properties
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On page 20 of the book \"Chemical Process Simulation Training–Aspen Plus Tutorial\", edited by Sun Lanyi, it is stated that \"the system in question consists of propylene, benzene, and isopropylbenzene, and it is a non-polar system.\" Based on what is learned in university, benzene is a non-polar molecule, but both benzene and isopropylbenzene are polar molecules; so why is the system composed of these three substances considered non-polar? Is it because benzene and isopropylbenzene have very low polarity that a non-polar system is chosen when using physical property methods?
There is no need to worry about it; according to the principle of similarity and compatibility, thermodynamics classifies substances as polar, non-polar, electrolytes, etc. Polar substances are further divided into highly polar and weakly polar ones. Organic compounds can be arranged in order of increasing polarity as follows: hydrocarbons, ethers, aldehydes, ketones, esters, alcohols, acids, water. Good luck! For reference only.
It should be calculated based on polarity, but it seems that all the binary interaction parameters are available, so the difference shouldn’t be too great
Original poster, have you figured out your question? I’m a beginner with Aspen, and I encounter this same problem when I reach this page. Please advise me, original poster!
Original poster, have you figured out your question? I’m a beginner with Aspen, and I encounter this same problem when I reach this page. Please advise me, original poster!