Fluid mechanics problems
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I need help from experts to analyze this process: When fluid flows laminarly in a circular pipe, if the flow velocity is doubled, the friction loss becomes () times the original value； If only the pipe diameter is doubled while the flow velocity remains unchanged, the friction loss will be () times the original value.
I haven’t reviewed Chemical Engineering Principles in too long; I’m almost forgetting it all
Fanning formula: hf = λ * l / d * u^2 / 2. If the flow rate is doubled, the resistance is quadrupled. So, the first one is 4 times. The laminar flow resistance formula is ΔPf=32*μ*l*u/(d^2). If the pipe diameter is doubled while the flow rate remains unchanged, the resistance is reduced by a factor of 4. So the second one is 1/4 times.
Just look up a book on chemical engineering principles and you’ll know