Calculate the concentration of fuming sulfuric acid

The concentration of fuming sulfuric acid can be determined by calculating the sum of the molar concentrations of its free SO3 and H2SO4. Suppose we have 100 ml of fuming sulfuric acid solution, of which the volume of free SO3 is 20 ml, and the volume of H2SO4 is 80 ml. According to the law of conservation of amount of substance, we can derive: n(SO3) + n(H2SO4) = N, where n(SO3) and n(H2SO4) represent the amounts of substance of free SO3 and H2SO4 respectively, and N represents the total amount of substance. According to the definition of molar concentration, we can convert the above equation to: C(SO3)·V(SO3) + C(H2SO4)·V(H2SO4) = N, where C(SO3) and C(H2SO4) represent the molar concentrations of free SO3 and H2SO4 respectively, and V(SO3) and V(H2SO4) represent the volumes of free SO3 and H2SO4 respectively. We already know that the volume of free SO3 is 20 ml, and the volume of H2SO4 is 80 ml. The percentages of free SO3 and H2SO4 are also given (20% and 80%), so we have: V(SO3) = 20 ml, V(H2SO4) = 80 ml. C(SO3) = 20% = 0.20, and C(H2SO4) = 80% = 0.80. By substituting these values into the equation above, we get: 0.20 * V(SO3) + 0.80 * V(H2SO4) = N. That is: 0.20 * 20 ml + 0.80 * 80 ml = N. By solving this equation, we can determine the value of N. Furthermore, the formula for calculating the molar concentration C of fuming sulfuric acid is: C = N / V, where N represents the amount of substance of fuming sulfuric acid, and V represents its volume. I hope this can be helpful to you! .