Calculation for base matching
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As titled: To dilute 1.2 m3 of 12% NaOH solution using 30% NaOH solution, how many cubic meters of 30% NaOH solution are required? How much water to add? Please provide the calculation process, thanks a lot.
Use 0.4 m3 of 30% caustic soda + 0.8 m3 of water
A+B=1200； A*0.3=1200*0.12 ； Find the values of A and B.
A*0.3*1.33=1.2*0.12*1.13； Find A
Are 1.33 and 1.13 the corresponding densities?
Use high concentration to dilute low concentration? I don’t know how to calculate the final concentration range either?
The concentration you need is the one you end up using; otherwise, what’s the point of preparing the base? I don’t know; wouldn’t it be better to take a break? Why go through all that trouble?