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In which of the following situations will there be no decrease in the temperature drop during the reforming reaction? (A) Nitrogen poisoning of the reforming catalyst; (B) Sulfur poisoning of the reforming catalyst; (C) Blending of coker gasoline into the feedstock; (D) High aromatic content in the feedstock. The correct answer is A, but I personally think that D could also be correct. Let’s discuss this – a high aromatic content in the feedstock should indeed lead to an increase in the temperature drop during the reforming reaction, right? Nitrogen poisoning of the catalyst reduces its acidity, lowers its isomerization capacity, and increases its metal-dehydrogenation capability, all of which result in an increase in the reaction temperature drop. It seems that both A and D are correct, but since this is a single-choice question, the answer is A
In this question, it asks which situation will not result in a decrease in the temperature rise during the reformation reaction. According to option A, the reforming catalyst is nitrogen poisoned; we know that the acidic functionality of the catalyst is reduced, and the drop in reaction temperature is caused by a decrease in its isomerization capability. Therefore, option A is the correct answer, as it will not cause a decrease in the temperature rise during the reformation reaction. However, the high potential content of aromatic hydrocarbons in option D leads to an increase in the temperature required for the reforming reaction, as aromatic molecules have a complex structure and require higher temperatures to undergo reforming. Therefore, option D is incorrect. In summary, based on the conditions described in the question, it will not lead to a decrease in the temperature rise during the reformation reaction; therefore, option A is the correct answer. .