The calculation issue of the long axis... is mainly a deformation issue
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I’ve been assigned a project involving an extremely long horizontal tank measuring 16x2 meters; the mixing mechanism is of the single-span type, with the diameter of the shafts at both ends estimated to be 320 mm, and it uses a frame-type mixer. Stirring speed: 20 revolutions per minute. Now the customer’s technical requirement is that the mixing blade should be kept about 3 mm away from the wall… The shaft deforms by 4 mm due to its own weight… Well, what should be done in this case? I’m a bit confused… Add another 320mm for the mechanical seal end? ? To what extent is it appropriate to add? Axial deformation 2.5mm, 2mm? ? Are there any standards or technical requirements to support this?
How long is the super-long shaft? How thick is it, and what’s its structure? What steps? What force is it? Could you show a simple diagram?
【Reply to Floor 2】 【Reply to Floor 2】 Hollow shaft, with an outer diameter of 965; wall thickness set at 70. The shaft diameter at both ends is 320, and shaft seals as well as internal support frames are provided respectively. The forces acting on it are its own weight plus a torque of 500 kilowatts. That’s all. Nothing else. The shaft’s own weight is 32 tons
A support device is added in the middle of the shaft; sliding bearings are used, and the number of supports is determined based on the amount of flexural deformation of the simply supported beam. The force exerted by the liquid on the shaft is specified in the book \"Comprehensive Book on Chemical Equipment Design – Mixers\", which is available on this forum
Sliding bearings are designed in the form of bushings, and maintenance of them can be quite difficult in the future. It is best to pre-install multiple bushings as spares; otherwise, replacing a bushing will require removing the shaft