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Composite level

2022-04-29View Original

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1. Purpose of the instrument: The synclinal level is widely used to measure the inclination of planes and cylindrical surfaces with respect to the horizontal direction, as well as the flatness, straightness of guides or bases in machine tools and optical instruments, and the accuracy of the installation position of such equipment. 2. Technical specifications: (1) Scale division value-----0.01 mm/m (2) Maximum measurement range-----0–10 mm/m (3) Indication error: within ±1 mm/m-----±0.01 mm/m; across the entire measurement range-----±0.02 mm/m (4) Flatness deviation of the working surface-----0.003 mm (5) Level scale value-----0.1 mm/m (6) Dimensions of the working surface (length*width)-----165*48 mm (7) Net weight of the instrument-----2 kg 3. Structure of the instrument: The compound level consists mainly of components such as a fine-adjustment screw, nut, dial, level, prism, magnifying glass, lever, and a base with flat and V-shaped working surfaces. 4. Working principle: The synoptic level uses a prism to amplify the optical alignment within the level, thereby improving the accuracy of readings. It employs a lever and a fine-adjustment screw as part of its transmission mechanism to enhance the sensitivity of the readings. Therefore, when the part under measurement is tilted by 0.01 millimeters per meter, it can be accurately read in the stereoscope. (In a combined level, the level tube primarily serves to zero the instrument.) ) 5. Usage: Place the combined level on the working surface of the part to be inspected. If the inclination of the surface causes the two bubble images not to align, rotate the dial until the two bubble images line up; at that point, the reading can be obtained. The actual tilt of the object being tested can be calculated using the following formula: Actual tilt = Scale value × Distance from the fulcrum × Dial reading. For example, if the dial reading is 5 units, for this type of combined level, both the scale value and the distance from the fulcrum are constant; the scale value is 0.01 mm/m, and the distance from the fulcrum is 165 mm. Therefore, the actual tilt = 0.01/1000 × 165 mm × 5 = 0.00825 mm. Question: The actual tilt is 0.00825 mm. How should this value of 0.00825 mm be interpreted?
Reply #22023-05-04
The length of the working surface of the integrated level is 165 millimeters; the value of 0.00825 mm represents the height difference over this 165 mm working surface length. The actual inclination should be calculated as 0.01/1000 * 5 mm/m. For example, if the distance between the shaft journals corresponding to two bearings is 2 meters, then the height deviation between those bearings is 0.01/1000 * 5 * 2000 = 0.1 mm

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