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Under normal circumstances, what diameter does an elliptical head require to justify being manufactured as a single plate?| Sequence | Item | Symbol | Calculation/Source of Data | Unit |
|----------|------|--------|--------------------------|------|
| 1 | Inner diameter of the head | Dn | Given | mm |
| 2 | Wall thickness of the head | t | Given | mm |
| 3 | Height of the straight edges of the head | h | Given | mm |
| 4 | Diameter at the neutral layer of the head | Dm | Dn + t | mm |
| 7 | Expanded diameter of the head | D | By equal-area method: D = √(1.38*Dm² + 4*Dm*h) mm; by equal-length method: D = 1.213*Dn + 1.5*h; by empirical formula: D = 1.19*Dm + 2*h | mm |
| 8 | Cutting allowance | △ | Determined based on the stamping equipment and process | mm |
| 9 | Diameter of the head blank | D0 | D0 = D + △ | mm |
The standard plate widths are usually 2400, 2200, or 2000 mm; one can calculate accordingly. It’s normal to use multiple plates for equipment where the required diameter is large, but it’s not appropriate to use multiple plates for very small diameters.