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Also known as the latent heat of evaporation, it is the heat of vaporization. The heat absorbed per unit mass of saturated liquid when it turns into dry saturated vapor under constant pressure conditions. During the vaporization process, the temperature remains at the saturation temperature corresponding to the pressure. So it is a form of latent heat. The latent heat of vaporization for any substance is equal to the difference between the specific enthalpy h″ of the dry saturated vapor at the same pressure and the specific enthalpy h′ of the saturated liquid. The latent heat of vaporization γ can be expressed by the formula γ = h″ – h′. Substances of different types have different values of latent heat of vaporization at the same pressure. For the same substance, the latent heat of vaporization decreases as the saturation temperature increases. For example, at 100°C (with a corresponding saturated pressure of 101 kPa), the latent heat of vaporization is 2257.2 kJ/kg. The latent heat of vaporization at 179.88°C (with a corresponding saturated pressure of 10 MPa) is 2015.4 kJ/kg, while it is zero at temperatures as high as 374.12°C (with a corresponding saturated pressure of 21.69×10 MPa). Can the latent heat of vaporization be found in which standard?
Name: Methane, Ethane, Propane, n-Butane, n-Pentane; Boiling point (°C) (101325 Pa): -162.6, -88.5, -42.1, -0.5, 36.2; Latent heat of vaporization (Kj/kg): 510.8, 485.7, 422.9, 383.5, 355.9
The latent heat of vaporization of propane at standard conditions is 402 KJ/Kg, but at 1.96 Mpa and 50 degrees Celsius, it is 273 KJ/Kg
A 1999 article in the Chinese journal \"Chemical Engineering Equipment Technology\" titled \"Estimation of the latent heat of gasification\" introduces various methods; I tried the Watson correlation method and obtained very accurate results. You can download it for reference. However, for a common substance like propane, the exact value can likely be found by consulting some chemical engineering design data manuals.