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SW6 calculates how longer storage tanks can have additional reinforcement rings to reduce wall thickness

2024-04-23View Original

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It’s a storage tank with a negative pressure of 0.1, made of Q235B material, with a diameter of 2400 and a height of 7500. The specified wall thickness cannot exceed 10 millimeters. Can I reduce this thickness by adding 2 flat steel reinforcement rings? For the external pressure calculation, I used 7500 divided by 3, which equals 2500; adding 1/3 of the head height gives 2700. The height on each side of the reinforcement rings is then 2700 + 2500, divided by 2, resulting in 2600. Does this calculation method work? I’m a beginner and not very familiar with this, so I’d appreciate some advice from everyone
Reply #22024-04-23
When calculating and designing long storage tanks that involve negative pressure, adding reinforcing rings is indeed a common method to reduce the wall thickness, thereby saving materials and reducing the structural weight. The calculation process you mentioned is roughly correct, but several key points need attention: 1. **Wall thickness and reinforcement ring settings**: Based on the information you provided, the tank’s diameter is 2400 millimeters, its height is 7500 millimeters, and the negative pressure is 0.1 MPa. In this case, the reinforcement ring can effectively reduce the required wall thickness. However, whether it can be reduced to below 10 millimeters requires detailed calculations. Your calculation method takes into account the division of the storage tanks, which is a correct initial step. 2. **Position and size of the reinforcement rings**: You mentioned dividing the storage tank into upper, middle, and lower sections, each approximately 2500 millimeters long, with reinforcement rings placed at the junctions between these sections. It is crucial to ensure that the width and thickness of the reinforcement ring are sufficient to withstand circumferential and longitudinal stresses. The specific dimensions and material selection need to be determined based on the specific operating conditions and design standards of the storage tank. 3. **Design and safety standards**: When carrying out the design, it is necessary to refer to relevant industry standards, such as GB 50341 \"Code for Design and Construction of Storage Tanks for Liquid Petrochemical Products\", to ensure that all designs meet safety requirements. Especially when dealing with negative pressure, both the structural stability and pressure resistance of the storage tank must be carefully evaluated. 4. **Calculation verification**: For beginners, it is very important to understand and apply calculation formulas accurately. It is recommended that after the design is completed, simulations be carried out using specialized software or that experienced engineers be consulted to review the calculation results, in order to ensure the safety of the structure. If you have specific design drawings or more detailed parameters, further discussion and analysis can be carried out. The design and calculation of reinforcement rings is a complex process that involves considering various factors. .
Reply #32024-04-23
1. The calculated length of the external pressure cylinder takes into account the straight section of the head; 2. When considering the nominal thickness of the head in terms of the reduction thickness, it is necessary to verify whether it meets the requirements, and the reinforcement at the pipe ends must also meet the specified standards ; If there is no impact, 10 is also fine. 3. The welding joint coefficient for the head is taken as 0.85 on an overall basis ; The coefficient for the weld joint of the manhole connection data page is the same as above. In conclusion, the thickness of the reinforcement ring is 12 mm.
Reply #42024-04-24
First, calculate the length for external pressure calculation. For an elliptical head with straight sides, the length for external pressure calculation is (2400/12 + 25) * 2 + 7500 = 7980. This length is then distributed evenly; if it is divided into three sections, two flat strips need to be added. In this case, the length for external pressure calculation becomes 7980/3 = 2660.
Reply #52024-04-24
Haha, this thing looks really good
Reply #62024-04-25
The principle is correct; the specific length shall comply with Section 4.3.1 of GB/T150.3-2011
Reply #72024-04-28
I often do the calculations myself; the comments are full of details
Reply #82024-04-30
Whether to use a welding coefficient of 1 or 0.85 depends on the actual circumstances. Given that the input parameters suggest it is not a pressure vessel, it is better to use 0.85. As for the design temperature, it should be determined based on the operating conditions

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