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May I ask, for an air flow rate of 100,000 units under specific operating conditions, with saturated flue gas at 60 degrees and a humidity level of 10%, how much heat can be released when the temperature is reduced to 45 degrees? I hope you can help me write out more specific steps. Thank you!
A. The air volume can be converted into weight (what is the density?). B. There is the temperature difference you desire. C. What is the specific heat of air? A*B*C = heat amount
First, figure out the components of the smoke gases, then determine their specific heat capacity; once that is known, the heat quantity can be calculated using the formula Q=cm△T.
Hello, I think I’m a bit confused about the specific heat capacity of smoke gases – it’s different when the moisture content is high or low, right?
Of course they’re different; the specific heat of water vapor is not the same as that of smoke, and since their water content differs, their properties will also be different.
Could you please help me create an equation using the above data? Treat the flue gas as moist air with 10% humidity. So, how much energy can be released when the temperature drops from 60 degrees to 45 degrees?
Flue gas flow rate: 100,000 cubic meters per hour; saturated flue gas temperature: 60 degrees; humidity: 10%; dust content: 100 mg/m3; NH3 content: 50 mg/m3. Thank you for your help
If you answer questions like this, I can’t help you either. Thank you.
It’s probably because there’s something I don’t quite understand; I’m not sure where the incorrect information came from. I’m sorry about that – it’s just that my knowledge isn’t sufficient. Thanks anyway!
Regarding the components of the flue gas you asked about, I previously said it can be considered as wet air, with no other components.