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Chloropropene storage material

2019-12-04View Original

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What material should be used for the condenser in the chloropropene condensation and reflux process? Can stainless steel be used?
Reply #22019-12-05
If chloropropene has a high water content, corrosion problems may occur... Metal is generally not recommended; graphite can be used instead....
Reply #32019-12-05
If it is stored after condensation, since the temperature is close to room temperature, carbon steel material will suffice
Reply #42019-12-06
It’s a condensation reflux condition, with a temperature of around 78℃
Reply #52019-12-06
If gaseous chloropropene needs to be condensed, a heat exchanger made of graphite can be used. The storage tank after passing through the heat exchanger can have a Teflon lining. PS: The temperature after condensation is 78 degrees?... At such a temperature, chloropropene remains in a gaseous state...
Reply #62019-12-06
Condense at 78°C below the boiling point; use 316 stainless steel with a thickness of 2 units. How long will it last? It would be good to know the annual corrosion rate
Reply #72019-12-06
So your question is phrased inappropriately... Gaseous chloropropene at 78 degrees needs to be condensed. Question 1: The material for the heat exchange device used for condensation... Graphite is recommended. Question 2: What material should be used to store the liquid chloropropene after it has been condensed? A container lined with Teflon can be used. What’s important to consider here is the corrosion rate compared to stainless steel! To be direct, pure chloropropene (without water) does not pose any problem for stainless steel; Basically, there is a trace amount of water present in chloropropene, which leads to the formation of hydrochloric acid. In the case of extremely dilute hydrochloric acid, pitting corrosion occurs much more frequently on stainless steel compared to uniform corrosion. As for the annual corrosion rate, that can be determined only considering uniform corrosion... I hope you understand the answer above.
Reply #82019-12-18
You explained it very clearly. I understand now, thank you

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