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How to solve a math problem

2021-05-25View Original

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Assume that the conductivity of the recycled water is divided by the conductivity of the make-up water. It is known that the conductivity of the recycled water is 2000. For the make-up water, one type is fresh water at a flow rate of 20 cubic meters per hour, with a conductivity of 600; the other type is reclaimed water at a flow rate of 30 cubic meters per hour, with a conductivity of 750. How should this be calculated?
Reply #22021-05-25
One type is fresh water at a rate of 20 cubic meters per hour, with a conductivity of 600; the other type is recycled water at a flow rate of 30 cubic meters per hour, with a conductivity of 750. In total, 50 cubic meters of water are added per hour. What is the conductivity of the water that is added?
Reply #32021-05-26
It seems like it’s just about finding the average, right? (20*600 + 30*750)/50 = 690. I’m not sure if that’s correct.

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