Solution to the calculation of water absorbing SO2 in examples of modern packed tower technology
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Guide to Modern Packing Tower Technology, edited by Wang Shuying. There are calculations in the examples regarding the absorption of SO2 by water; on page 248, I don’t understand the part shown as a cloud diagram. It shouldn’t be 8.314*T – why is it 0.082*100*T? I’m confused about this point; could someone please help explain it? Thank you
Consider the units of the ideal gas constant. R = 0.082 has units of (L atm)/(mol K), whereas R = 8.314 has units of J/(mol K). If the pressure and volume are given in atmospheres and liters respectively, then the value R = 0.082 should be used. If the pressure is expressed in pascals and the volume in cubic meters, then R = 8.314 is to be used (the same applies when pressure is in kilopascals and volume in liters, since 1 kPa = 1000 Pa and 1 L = 1/1000 m^3). These two values of R represent the same physical quantity; the difference between them is due to the different units used. In fact, R = 8.314 is the more important value as it is expressed in SI units (note that 1 J = 1 Pa * m^3 = 1 N/m^2 * m^3 = 1 N * m).
R=PV/T=22.4/273.15=0.082 Thank you; with a reminder, I was able to understand it.