How is the resistance coefficient of a reducer determined? I don’t understand

2023-03-18View Original

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This post was last edited by LoveToPlayPrimarySchoolStudent on 2023-3-18 at 15:38. Recently, while reviewing the calculations related to pipe fluid dynamics in the fifth edition of the \"Chemical Process Design Handbook,\" I have some doubts regarding the values of the resistance coefficients for reducers used in the examples. How are the resistance coefficients of 0.55 + 0.17 for reducers determined? For personal computing, the interpolation method is used; for 50 to 40 diameter reduction fittings, Ka=0.125, Kb=0.0525, and Ka+Kb=0.1775 ； 40 to 50 reducer, Ka=0.125, Kb=0.32, Ka+Kb=0.445. In that case, the two reducers should be 0.1775 + 0.445. I’m not sure if there might be an issue with this calculation

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How is the resistance coefficient of a reducer determined? I don’t understand

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