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Gas composition by mol%: Methane 7.2; CO2 13.1 ; N2 69.7 ; H2O 2.6 ; O2 7.4. How can one determine whether this gas is explosive? It does not refer to leakage into the air, but only applies to the gas itself.
Among them, only methane is a flammable gas; you can check the explosive limit concentration range for methane as a reference.
Let’s assume that the most intense explosion occurs when the volume fraction of methane in air reaches X; at this point, methane reacts completely with oxygen. The reaction is CH4 + 2O2 = CO2 + 2H2O. Since the oxygen content in air is 21%, at the moment of the most intense explosion, the volume of oxygen in one unit volume of air is (1-X)*21%, while the volume of methane is X. Therefore, (1-X)*21% = 2X → 0.21 – 0.21X = 2X. Solving for X gives X = 0.095. Thus, the most intense explosion occurs when the volume fraction of methane in air is 9.5%. Replace 21% in the formula with 7.4.
5%–15% is the explosive limit of methane
Mmhm, well I can’t do it; usually I try using a matchstick. :lol
It is possible to check the oxygen concentration limit for methane; if this value is not exceeded, no explosion will occur regardless of the methane concentration
Is this an injection molding exam question? It seems to require a high level of understanding of basic concepts
Chemistry exam questions? It’s not simple at all~~
Consider it based on the explosive limit of methane
Still proud of it? What era is this? Try with a matchstick again? Do you know of a device called a portable combustible gas detector? Using matches to light things is an old practice from years ago; it’s very dangerous! :lol