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Saturation steam at 10 BAR passes through a flow control orifice plate, where its pressure is reduced to 7 BAR, resulting in superheated steam at 7 BAR? How does the traffic change? Please ask~
Theoretically, it is isentropic depressurization: the temperature remains constant while the pressure decreases, which naturally results in superheating. The traffic remains unchanged. There is actually energy loss, but it is not noticeable when the flow rate is high.
In practical operation, if the amount of steam is not large, a steam pressure reducing valve can be used directly; by reducing the pressure, the temperature also decreases to some extent. Due to heat losses in the pipes, it remains saturated steam. However, if it is a large amount of steam, it is not recommended to do this; instead, use a temperature and pressure reduction device, add an appropriate amount of cooling water, and then use the resulting steam. Indeed, as mentioned on the 2nd floor, when a large amount of steam is depressurized directly, overheating can occur. However, since it cannot be a strictly isentropic process, the degree of overheating is not significant; downstream of the pipe, the steam quickly reaches a normal saturated state, and some water may even condense.
I think the quality of superheated steam obtained solely through pressure reduction using orifice plates is not very high
The mass flow rate remains constant, while the volume flow rate increases
According to the law of conservation of mass, as much enters as exits, so the flow rate remains constant. Otherwise, there will be continuous accumulation or continuous intermediate release
If the aperture remains unchanged, the flow rate will not change.