I need an expert to help me figure out the conversion between steam and water
Thread Content
For 0.5MPA steam at 155 degrees, when it drops to 0.3MPA and 130 degrees, how many tons are needed to raise the temperature of 200 tons of water from 100 degrees to 130 degrees?
It’s simply a matter of heat balance; by looking up the corresponding enthalpy values and the latent heat, the calculation can be done
Agree with the third floor. Here is a set of data provided for the original poster: the enthalpy of unsaturated water at 0.5 Mpa and 150°C is 632 kJ/kg； The enthalpy of unsaturated water at 0.3 Mpa and 130℃ is 546 kJ/kg ； The enthalpy of unsaturated water at 0.3 Mpa and 100℃ is 419 kJ/kg. The original poster can calculate it themselves by considering the specific heat exchange methods; what if it’s told that 300 tons of steam are needed, but the amount of material that needs to be heated ends up being over 500 tons? ;P;P
The original poster is being lazy – the evaluation is complete! :lol