Seeking information on the vaporization temperature of propane
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Liquid propane enters the vaporizer from the spherical tank; the pressure at the exit of the vaporizer is 0.6 MPa. To what temperature needs the liquid propane to be heated after entering the vaporizer in order to ensure complete vaporization? After entering the pipeline network, the pressure inside it is around 0.35. How much temperature is needed to ensure continuous vaporization during the transport of about 2 km from the starting point to the farthest device?
The vaporization temperature of propane is related to pressure; under normal conditions, the saturated vapor pressure of liquid propane at room temperature (around 20°C) is approximately 0.5 MPa. Therefore, at a pressure of 0.6 MPa, the vaporization temperature of propane should be around 30°C. As for the temperature to which liquid propane must be heated to ensure complete vaporization, this depends on factors such as the design of the vaporizer and the conditions of convective heat transfer. If you do not have reliable data and design parameters, it is recommended to refer to relevant process manuals or consult professionals in the field. Furthermore, the temperature required to keep propane in a gaseous state over a distance of about 2 km from the starting point to the farthest device also depends on various factors such as the design of the pipeline, the material and thickness of the insulation layer, and environmental conditions. It is recommended to carry out detailed pipeline design and calculations to ensure that propane remains in a gaseous state throughout transportation. .
First, it is necessary to calculate the flow rate of propane in the pipeline in order to determine the required heating temperature. Based on the information you provided, with a pipe diameter of 150 mm and a pipeline pressure of 0.35 MPa, the flow rate of propane can be calculated using the following formula: Q = 3.14 * D^2/4 * V, where D is the inner diameter of the pipe in meters, and V is the flow rate of propane in m/s. Setting Q to 1 m³/h (assuming a propane flow rate of 1 m³/h), we have: 1 = 3.14 * 0.15^2/4 * V, which gives V = 0.8898 m/s. Next, by consulting tables or using steam calculation software, it can be determined that at a flow rate of 0.89 m/s, the vaporization temperature of propane is approximately -5°C. Therefore, liquid propane needs to be heated above -5°C in order to remain in a gaseous state at all times. The specific heating temperature depends on factors such as whether the pipeline is insulated, the transportation distance, and the ambient temperature; it is recommended to carry out detailed design and calculations. .
Bro, where did you get the data on saturated vapor pressure and temperature from? Thank you
Thank you, sir, for providing such a detailed explanation of the calculation process