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How is the maximum flow rate of a pipeline calculated?

2024-07-30View Original

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This post was last edited by *nht1 on 2024-8-3 08:41. As the title suggests, how is the maximum flow rate of a pipeline calculated? Many books calculate pipe flow rates based on economic flow velocities. So, if the flow is allowed to proceed without regard to whether it’s economical or not, can the maximum flow rate still be calculated? Theoretically, the faster the flow rate, the greater the pressure drop. The maximum flow rate occurs when the pressure drop in this pipe equals the pressure difference between the two ends; at that flow rate, it is the fastest, and thus the flow volume is the greatest. But in many cases, when a pipe is opened to allow self-priming, the fluid pressure at the outlet of the pipe is not zero; that is, even in the case of self-flow, the flow rate does not eliminate all the pressure. In such situations, it cannot be considered an economic flow rate – but can the maximum flow rate still be calculated? The calculation of this flow rate should have practical engineering significance. For example, when considering the maximum breathing capacity of a tank’s breather valve, the flow rate in the nitrogen seal line should be calculated based on the maximum flow rate rather than the maximum flow rate at an economic flow velocity.
Reply #22024-07-30
To calculate the maximum flow rate of a pipeline, it usually involves some basic equations from fluid dynamics as well as practical engineering considerations. Without considering the economic flow rate, we can proceed from the following aspects: 1. **Bernoulli’s equation**: Used to describe the conservation of energy in flowing liquids within an ideal fluid. In fluid dynamics, the Bernoulli equation can be expressed as: \ where \( p \) is pressure, \( \rho \) is density, \( v \) is flow velocity, \( g \) is the acceleration due to gravity, and \( h \) is height. In horizontal pipes, the height term can be ignored. 2. **Darcy-Weisbach equation**: Used to calculate the pressure loss in pipes due to friction. The formula is: \ where \( \Delta p \) is the pressure drop, \( f \) is the friction factor, \( L \) is the length of the pipe, and \( D \) is the diameter of the pipe. 3. **Flow formula**: The flow rate \( Q \) can be calculated using the flow velocity \( v \) and the cross-sectional area \( A \) of the pipe: where the cross-sectional area \( A = \pi \cdot \left(\frac{D}{2}\right)^2 \). When calculating the maximum flow rate, what we need to consider is the highest flow velocity at which the pressure loss caused by the fluid flowing through the pipe equals the given pressure difference (the pressure difference between the upstream and downstream sides of the pipe). This usually requires simplifying and combining the above equations, as well as finding the maximum value of the flow velocity \( v \), in order to determine the maximum flow rate \( Q \). However, in engineering applications, the calculation of the maximum flow rate also requires taking into account the physical properties of the fluid (such as viscosity and density), as well as factors such as pipe material and temperature. For complex systems, it may be necessary to use fluid dynamics software or experimental data to accurately evaluate the maximum flow rate. .
Reply #32024-07-31
If the pipe’s strength is sufficient and its diameter is large enough, then the flow rate through this pipe can be infinite. When discussing the maximum flow rate of a pipeline, if the material, strength, diameter, and transmission distance of the pipeline are not specified, nor is the state, temperature, pressure, and/or pressure difference of the medium, then my answer above should be fairly accurate.
Reply #42024-07-31
I didn’t see your reply above. Could you please send it again? Thank you. Furthermore, this issue is considered based on the actual conditions of a real engineering project: the material is ordinary carbon steel (with a known friction coefficient), the pipe diameter and length are fixed, as well as the pressure difference at the pipe inlet and outlet; the flow is allowed to occur freely, without taking into account an optimal flow velocity. What would be the actual flow rate in such a case?
Reply #52024-07-31
Similarly, the flow rate in the heat exchanger is the same; if there are no flow control valves, how can we be sure that the circulating water in the heat exchanger flows at the calculated rate? Why doesn’t it flow at the maximum allowable pressure drop? https://bbs.hcbbs.com/thread-5668467-1-1.html
Reply #62024-07-31
When working on engineering projects, it is necessary to consider the principles of technical feasibility and economic Reasonableness. Just look at the Bai Effort Equation and you’ll know the answer.
Reply #72024-07-31
The flow rate of materials in a closed pipeline system is influenced by many factors, such as the physical properties of the materials themselves, pressure, temperature, etc. For example, the flow rate of hydrogen is different in stainless steel pipes and carbon steel pipes, and it also varies depending on pressure (see GB50177). For example, the flow velocity of natural gas in pipelines is usually 15–25 meters per second, but it is higher inside control valves; therefore, it also depends on different materials and process conditions.
Reply #82024-07-31
The question you raised actually relates to the two modes used in calculating pipe resistance: one is the design mode, in which an economical flow velocity is chosen to determine the pipe diameter, and then pipe resistance is calculated; There is also a verification mode, where given the pipe diameter and the maximum pipe resistance, the maximum flow velocity is calculated inversely.
Reply #92024-07-31
I can’t just set the maximum pipe resistance and expect it to operate based on that resistance, right? In actual operation, how is the resistance determined? It should be by looking at the pressure difference between the inlet and outlet; the greater the pressure difference, the more fluid can flow. The flow rate stops increasing when the pressure loss equals the pressure difference between the two ends. Is this understanding correct?
Reply #102024-08-01
Learned*: hug::hug:

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