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There is an organic reaction carried out in a reactor, where liquid compound A + liquid compound B === liquid compound C (the main reaction). But at the same time, 4 side reactions occur, namely A+ B==H2O, A+B==D, A+B==E, and A+B==F. D, E, and F are also liquid compounds with boiling points different from that of C. Moreover, at normal temperature and pressure, the boiling points of C, D, E, and F also differ significantly. However, in the system after the reaction, H2O will form \"binary azeotropes\" or \"multicomponent azeotropes\" with products such as C, D, E, F, as well as the unreacted starting materials A and B. Therefore, it is very difficult to separate and purify the target product C to a purity of over 99.0% using the conventional “multi-column distillation process”. Now, it is desired to use an inorganic adsorbent to directly adsorb and remove the H2O generated after the reaction (with a mass content of around 15 wt%) at temperatures of 220–240°C and pressures of 7.0 MPa, thereby reducing the \"azeotrope\" formation between the aforementioned substances and H2O, and making subsequent distillation, separation, and purification processes easier. This enables the unreacted starting material liquid compounds A and B to be purified to over 95.0%, while the target product C can be purified to over 99.0%. Please tell me, under the aforementioned process conditions, which inorganic adsorbent can achieve the goal of adsorbing water? It is required to be able to adsorb at less than 0.5 wt%. It is best if this inorganic adsorbent contains \"phosphate groups\"; \"molecular sieve adsorbents\" are also an option. Adsorbents that do not contain phosphate groups, such as CaCl2, Na2SO4, or MgSO4, should be avoided. If anyone who knows knows about it, please let me know; I’d be extremely grateful!