How to understand logical SR?
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I don’t understand; S sets it, R resets it
The RS flip-flop, as you mentioned, has one terminal for setting and one terminal for resetting
r is 0, s is 1, the result is 0?
When the S contact is closed, the result is 1; when the R contact is closed, the result is 0. You can find out by searching on Baidu.
Just take a look at digital technology and you’ll understand
In general functional blocks, there are two types: SR and RS. In the RS case, R has a higher priority; when both S and R are 1, the result is 0. In the SR case, S has the higher priority, and even when both S and R are 1, the output remains 1. In either case, when S is 1 and R is 0, there is no conflict, and the result is 1.
RS: R S Q 0 0 remains unchanged 0 1 1 1 0 0 1 1 0