HCBBS Forum (English)
Submit Chemical Projects / Find Solutions
Amplify Your Requirements on a Broader Chemical Platform *Engineering · Technology · Equipment · Solutions*
Submit Request

Process Engineering Division – Instrumentation and Automation Section – Daily Topics – Topic No. 2020-12-15

2020-12-15View Original

Thread Content

Process Engineering Division – Instrumentation and Automation Section – Daily Topics – Topic No. 2020-12-15: Discussion question: 327. If the mass flow rate of steam is M=100 t/h, what should be the inner diameter D of the pipeline? If the density of the steam is ρ=38 kg/m3, what is the average flow velocity of the steam in the pipe? (5 points are given only to those who provide the correct answer; additional points are awarded for a correct calculation process or detailed explanation.)
Reply #22020-12-15
s=(M*1000/38 /3600)/*1000000=23.28m/s
Reply #32020-12-15
s=(M*1000/38 /3600)/*1000000=23.28m/s
Reply #42020-12-15
s = (m*1000/38 / 3600) = (100*1000/38/3600) = 23.28 m/s; the average speed is 23.08 m/s.
Reply #52020-12-15
s=(M*1000/38 /3600)/*1000000=23.28m/s
Reply #62020-12-15
s = (m*1000/38 / 3600) = (100*1000/38/3600) = 23.28 m/s; the average speed is 23.08 m/s.
Reply #72020-12-15
s=(M*1000kg/h/38kg/m3 /3600s)/*1000∧-2m2=23.28m/s
Reply #82020-12-15
If the mass flow rate of steam is M=100 t/h, the selected inner diameter of the pipe is D=200 mm. If the density of the steam is ρ=38 kg/m3, what is the average flow velocity of the steam in the pipe? Solution: The relationship between mass flow rate and volume flow rate is: mass flow rate = density multiplied by volume flow rate (M = ρQ). Therefore, Q = M/ρ = 100*1000/38 = 2631.58 m3/h = 0.731 m3/s. The cross-sectional area of the pipe, S, is equal to 3.14*(D/2)2 = 3.14*0.01 = 0.0314 m2 ; The average flow velocity of the steam in the pipe is u = Q/S = 0.731/0.0314 = 23.28 m/s. Answer: The average flow velocity of steam in the pipeline is 23.28 m/s.
Reply #92020-12-15
s = (m*1000/38 / 3600) = (100*1000/38/3600) = 23.28 m/s; the average speed is 23.28 m/s.
Reply #102020-12-15
The relationship between mass flow rate M and volume flow rate Q is M = ρQ; therefore, Q = M/ρ. Hence, Q = 100 / ρ = 2631 kg/m3. The cross-sectional area of the pipe, S, is given by S = π/4 · D2 = π/4 (0.2)2 = 0.0314 m2. Since Q = SU, the average velocity of the steam, U, is calculated as U = Q/S = 0.731 / 0.0341 = 23.3 m/s
Reply #112020-12-15
s=(M*1000/38 /3600)/*1000000=23.28m/s

Submit a Project

**Looking for Chemical Technology, Equipment & Solutions?** No Registration Required Broader Platform Exposure | Global Chemical Service Provider Connections

Submit Request — Free Consultation

Disclaimer

This is an automated machine translation of the original thread. Some technical terms may have inaccuracies; the original text shall prevail. Click "View Original" at the top right to access the source page, which supports IP-based automatic real-time language translation. Please watch out for contact details and sales inducements to prevent fraud. All content and translations are for reference only, representing solely the poster's personal views. For enquiries, email service@hcbbs.com.