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What is the production principle of H2S removal from liquid sulfur? Answer: The principle of H2S removal from liquid sulfur is as follows: Liquid sulfur comes into full contact with air in a bubbling column, which causes the polysulfides present in the liquid sulfur to decompose. At the same time, the H2S in the liquid sulfur reacts with O2 to form sulfur, while some of the H2S enters the gas phase along with the air and is then pumped to an incinerator for combustion, thereby removing the H2S from the liquid sulfur. This process can be represented by the following reaction equations: H2S8 == H2S + 7S, 2H2S + O2 == 2S + 2H2O
H2S reacts with O2 to produce sulfur, thereby removing H2S from liquid sulfur. This reaction can be expressed as follows: H2S8 == H2S + 7S; 2H2S + O2 == 2S + 2H2O
H2S gas reacts with oxygen in the air to produce elemental sulfur.
H2S reacts with O2 to produce sulfur, thereby removing H2S from liquid sulfur. This reaction can be expressed as follows: H2S8 == H2S + 7S; 2H2S + O2 == 2S + 2H2O
H2S reacts with O2 to produce sulfur, thereby removing H2S from liquid sulfur. This reaction can be expressed as follows: H2S8 == H2S + 7S; 2H2S + O2 == 2S + 2H2O
Answer: The production principle of H2S removal from liquid sulfur is as follows: Liquid sulfur comes into full contact with air in a bubbling column, which causes the polysulfides present in the liquid sulfur to decompose; at the same time, the H2S in the liquid sulfur reacts with O2 to form sulfur
H2S reacts with O2 to produce sulfur, thereby removing H2S from liquid sulfur. This reaction can be expressed as follows: H2S8 == H2S + 7S; 2H2S + O2 == 2S + 2H2O