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In the Tianjin University textbook, in section 5.5-9 on absorption processes, when the desorption factor S is kept constant, the composition Y1 of solute A in the gas phase entering the tower increases...

2018-08-13View Original

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This post was last edited by yiyuguchen on 2018-8-13 at 14:19. In the textbooks from Tianjin University, in section 5.5-9 regarding absorption processes, when the desorption factor S remains constant and the composition y1 of solute A in the gas entering the tower increases, how will the absorption rate of this solute change? The answer is that the absorption rate remains constant; the solute absorption rate = (y1 – y2)/y1 = 1 – y2/y1. Since the absorption rate stays the same, y2/y1 also remains unchanged. The desorption factor S = mV/L, and since this factor remains constant, it means that the slope of the absorption operation line remains unchanged as well. I’m not quite sure how this condition leads to y2/y1 remaining constant; could everyone please help me out? Thank you!

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