What is the denitration mechanism of NACIO2 solution?

NaClO2 is a white crystal or crystalline powder with slight hygroscopicity; it is soluble in water and possesses strong oxidizing properties. The reaction of wet-based removal of NO from solutions is relatively complex. Many scholars, after conducting research in this area, believe that it is an absorption-oxidation reaction controlled by a gas film; NOx is primarily absorbed through the hydrolysis of N2O3 and N2O4, while NO can be quantitatively oxidized in aqueous solutions by NaClO2. In this reaction process, NO is oxidized to NO-3, while ClO-2 is converted into Cl- and ClO-. Therefore, it is believed that the reaction between NO and NaClO2 in an alkaline solution is as follows: NaClO2 → Na+ + ClO2-; 2NO + ClO2- → 2NO2 + Cl-; NO + ClO2- → NO2 + ClO-; 4NO2 + ClO2- + 4OH- → 4NO3- + Cl- + 2H2O; NO2 + ClO2- + 2OH- → 2NO3- + ClO- + 2H2O. Since HNO3 is formed, the pH value of the solution drops rapidly in a short period of time. NaClO2, on the other hand, decomposes in an acidic solution, with the following reaction pathways: ClO2- + H+ → HClO2; 8HClO2 → 6ClO2 + Cl2 + 4H2O; 2ClO2- + Cl2 → 2Cl- + ClO2; 4ClO2- + 2H+ → 2ClO2 + ClO3- + Cl- + 2H2O. The oxidation reactions of NO are as follows: 4NO + 3ClO2- + 2H2O → 4HNO3 + 3Cl-; 5NO + 4HCl → 4ClO2 + 5Cl- + 2H2O; 5NO + 3ClO2 + 4H2O → 5HNO3 + Cl-

Under acidic conditions, the oxidation reaction of NO is as follows: 2NO + ClO2- + ClO- + H2O = 2NO3- + 2Cl- + 2H+