Questions regarding drying room design.
Thread Content
There is sludge that needs to have its moisture removed, from an 80% water content to 30%. Can 600 kilograms of 0.6-kilogram saturated steam every 8 hours evaporate 3.57 tons of water? Please ask someone who knows how to calculate to do it.
80,000 hours won’t work either: Do you want to turn 1 kilogram of ore into 1 ton of gold?