If it is both a base shaft system and a base hole system, is it definitely a clearance fit?
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If it is both a base shaft system and a base hole system, is it definitely a clearance fit? Since the lower deviation in the base hole system is 0 and the upper deviation in the base shaft system is 0, a system that is both based on the base shaft system and the base hole system must result in a clearance fit. Is that correct?
How is it possible to be both a base shaft system and a base hole system at the same time? Only by establishing standards can fit be determined through tolerances
Hello, then what combination is H8/h8?
It is impossible to be both in the base shaft system and the base hole system
Which novice designed these tolerances? Holes are more difficult to machine than shafts; the tolerance for shafts is 8, so was the tolerance for holes also set at 8?
Interference fits of H/h do exist, but the H8/h8 combination is rarely seen; H7/h6 is a more reasonable choice.
Hello, thank you for your participation. There is definitely a combination for H8/h8; it can be found in the standard combination table. What I want to determine now is whether, in the case of both the base hole system and the base shaft system, it is definitely a clearance fit I just want to discuss it and ask for some advice; thank you.
Hello, thank you for your participation. There is definitely a combination for H8/h8; it can be found in the standard combination table. What I want to determine now is whether, in the case of both the base hole system and the base shaft system, it is definitely a clearance fit I just want to discuss it and ask for some advice; thank you.
The double H fit generally appears in assemblies with locking devices; I believe the minimum tolerance for double H is 0, and it should be a clearance fit.
Theoretically, this is a clearance fit, but it is generally not used in applications that require frequent relative movement. If other form and position tolerances are taken into account, there is still a chance that there will be some interference. The concentricity of the H/h tolerance is better than that of H/g, and it is also easier to assemble compared to interference fits such as H/m(k); therefore, it is still widely used.
Thank you for your reply; I just wanted to discuss it, as I share the same thoughts as you.