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How should we understand that the impact energy values for small-scale impact specimens with a width of 7.5 mm or 5 mm are 75% or 50% of those for standard specimens, respectively?
It is because the raw materials, for certain reasons (for example, steel plates or pipes with a thickness of 12 mm or less cannot be processed to achieve a thickness of 10 mm), make it impossible to establish a standard time of 10*10*55; therefore, only small specimens with a thickness of 7.5 mm or 5 mm can be used. The acceptable values for impact energy are set at 75% or 50% of the acceptable values for standard specimens.
For example, if the material thickness is 12 mm, the impact specimen used is 10*10*55, and the acceptable value is 47 J. . For a base material of 10 mm, the impact test value used is 7.5*10*55, and the acceptable value is 47X75%. For a base material of 7 mm, the impact test value used is 5*10*55, with the acceptable value being 47X50%
The standard specimen has a width of 10 mm; impact specimens with widths of 7.5 mm or 5 mm account for 75% and 50% of the cross-sectional area of the standard specimen (10 mm), respectively. Therefore, the impact energy values are 75% or 50% of those of the standard specimen, respectively
Impact work is equivalent to the energy absorbed by impact; a smaller specimen will absorb less energy, so it’s sufficient to scale it down proportionally!
It’s similar to weight – something that is 10 mm wide weighs 1 kg, while one that is 5 mm wide weighs 0.5 kg. It scales proportionally; however, the thickness might not necessarily scale in the same way:lol:lol