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How to determine the speed and power of a motor?

2016-04-08View Original

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I’m a complete beginner and am learning as I go~ A motor of grade 2 is used, along with a pulley system, to rotate a barrel with a diameter of 360 mm at a speed of 900 r/min. The weight of the barrel is 9 KG. I found the formula P=TN/9550; should the torque T in this formula be calculated as 9x9.8x0.18=15.88 N·m? Then, by dividing 15.88 by the speed ratio of 2880/900, the minimum torque would be 4.96 N·m, right? Is the power P=4.96x2880/9550=1.5KW? Is this calculation correct?
Reply #22016-04-09
Weight should not be used directly; moment of inertia should be used instead
Reply #32016-04-09
You need to use a reducer for this; otherwise, you won’t be able to change the input speed; After calculating, I think you can just go with a 0.75KW motor! There’s no need for something as powerful as 1.5KW!
Reply #42016-04-11
As a supplementary note: the radius of rotation of the cylinder is 150 mm. The cylinder is connected by shaft a, and the weight of the cylinder plus shaft a is 10 kg. Shaft a is connected to a pulley with a diameter of 160 mm. If it is to rotate at a speed of 900 r/min, what would be the power required if a 2-stage motor is used? Is it feasible to use a 225mm pulley for the motor? I’m not very familiar with this area, so I hope you can help answer my questions. If there are any additional parameters needed, please let me know. Thank you in advance

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