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How to understand the pumping capacity of a steam ejector?

2016-04-21View Original

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I saw a definition of the pumping volume of jet pumps in standard 8540, but I don’t quite understand it; could you please explain? What does it mean to specify in terms of equivalent air? For example, if my flow rate is 100 KG/H with a molecular weight of 23, do I need to convert it to an air flow rate first before determining the pumping volume?
Reply #22016-04-26
Yes, convert it to equivalent air or equivalent water vapor, and then use that to carry out the design calculations. Testing is also carried out using equivalent air or equivalent water vapor.
Reply #32016-04-26
I had the opportunity to contact the standard drafter, who said that the exhaust volume is equivalent to your gas consumption, and no conversion is necessary.
Reply #42016-05-06
Yes, it is calculated by determining the equivalent amount of air based on the molecular weight of the material and the temperature, and then further calculations are performed.
Reply #52016-05-06
I had the opportunity to contact the standard drafter, who said that the exhaust volume is equivalent to your gas consumption, and no conversion is necessary.
Reply #62016-05-06
Uh. . . . JB/T8540-2013 is a standard established by our company. For users, it is sufficient to specify the operating conditions; the quality conversion is carried out by the designers during the calculation of the injector.
Reply #72016-05-09
Hangzhou Longda? I don’t quite understand; since it’s a mass flow rate, how is it converted? Or do you actually choose the model based on flow rate, converting that flow rate into the mass flow rate for different gases?
Reply #82016-05-10
It needs to be converted; this is the internationally accepted standard; Converted to equivalent air or equivalent water vapor, this is the standard in both Europe and the United States. From the perspective of the principle of ejectors, it is incorrect not to make such conversions, as ejectors are classified as momentum-transfer vacuum pumps, and their performance is highly dependent on molecular weight and temperature.
Reply #92016-05-16
Agree with the opinion on floor 8. By the way, I’m from Hangzhou Huada. . . . Londa was developed later as a separate option. For example, when pumping 100 kg/h of hydrogen or 100 kg/h of air under the same operating conditions, users specify the parameters based on 100 kg/h; however, designers must distinguish between hydrogen and air. As a result, the equipment selected for pumping hydrogen will definitely be more powerful than that used for pumping air.

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