How much hydrogen and nitrogen are required to produce one ton of synthetic ammonia?
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Please list the formulas
N2 + 3H2 == 2NH3. Under standard conditions, the number of moles in one ton of ammonia is: 1000 kg / 17 g/mol = 58.82 kmol. Therefore, 29.41 kmol of N2 is required; this corresponds to 29.41 kmol * 22.4 L/mol = 658.7 Nm3 of N2. 88.23 kmol of H2 is needed as well, which equals 88.23 * 22.4 = 1976 Nm3 of H2. The actual volume of the nitrogen-hydrogen mixture required is: 58.82 kmol * 22.4 * 2 = 2635 Nm3