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Equivalent diameter in the heat transfer process

2016-05-25View Original

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I’m seeking help from experts: how is the equivalent diameter calculated in the heat transfer process? The formula is =4*wetting area/heat transfer wetting perimeter; I don’t quite understand it. For example, in the process of film condensation, if the side length of a square vertical plate is a, then the wetting area is a*a, and the wetting perimeter is 4a. So why do I see in books that the wetting perimeter is given as 2a? May I ask, in the process of film condensation is it calculated based on the downward flow of the condensate, and should the heat transfer flow cross-sectional area be a*b (assuming b is the thickness of the liquid film)? ; And the heat transfer perimeter is 2(a+b); since b is much smaller than a, it can be approximated as 2a?
Reply #22016-05-25
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