2013, Basic Professional Knowledge, Question 35: Issue of extraction yield
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The images online aren’t very clear; the question seems to be as follows: Use 835 KG of pure water to extract acetic acid from a mixture containing 35% acetic acid. The amount of the feed solution is 1000 KG, and it is required that the acetic acid content in the raffinate phase be reduced to 7%. The volume of the resulting raffinate phase is 675 KG. What is the extraction efficiency of acetic acid? The answer is 86.5%. How is this calculated?
It's simple. The raw material solution weighs 1,000 kilograms, with an acetic acid content of 35%, meaning the mass of acetic acid is 350 kilograms. The extraction residue phase weighs 675 kilograms, with an acetic acid content of 7%, which is equivalent to 47.25 kilograms. The actual extraction rate is 350 minus 47.25, divided by 350, which equals exactly 0.865
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