Transformation problem
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With all other conditions unchanged, what will happen to the shift reaction temperature if the amount of feed gas is reduced? Personally, I think the volume of air decreases; the carbon monoxide concentration remains unchanged, but the residence time increases, so the temperature rises. What do you all think?
It should be the drop in temperature; as the amount of feed gas decreases, less gas participates in the reaction, and thus the heat generated by the reaction also decreases
But the reactor volume remains unchanged, the carbon monoxide concentration remains unchanged, yet the residence time is long
The hot spot moves upward, the bed temperature rises, but the actual heat load decreases.
Even if the residence time is longer, the amount of active gas participating in the reaction decreases, and the reaction heat also decreases
It depends on how much the amount is reduced. From my practical experience, when the reduction is significant, the furnace temperature rises rapidly; over time, this temperature then drops. If the reduction in amount is smaller, the furnace temperature also decreases. Hope this helps you
Thank you. This might be due to two factors: one is the residence time, and the other is the reduction in the amount of reaction gas; it depends on which factor has a greater impact.